### Article Index

#### a. Traverse with Bearings

 Figure E-6 Bearing Traverse Example

 Line Bearing Length (ft) Lat (ft) Dep (ft) AB S 68°05'35"W 472.68 -176.357 -438.548 BC N 19°46'00"W 216.13 +203.395 -73.093 CD N 45°55'20"E 276.52 +192.357 +198.651 DA S 54°59'15"E 382.24 -219.312 +313.065 sums: 1347.57 +0.083 +0.075 Distance Lat err too far N Dep err too far E

##### (1) Adjust the Lats and Deps

Setup Equations E-1 and E-2:

Now solve Equations E-3 and E-4 for each line:

Line AB

Line BC

Line CD

Line DA

Check the closure condition

 Adjusted Line Lat (ft) Dep (ft) AB -176.386 -438.574 BC +203.382 -73.105 CD +192.340 +198.635 DE -219.336 +313.044 sums: 0.000 0.000 check check

A common mistake is to forget to negate Lat err and Dep err in the correction equations. If that happens, the closure condition will be twice what it originally was as the corrections were applied in the wrong direction.

##### (2) Compute adjusted lengths and directions

Use Equations E-5 and E-6 along with Figure E-5 to compute the new length and direction for each line.

Line AB

Adj Lat = -176.386 <- South
Adj Dep = -438.574 <- West

Because it's the SW quadrant, Brng =S 68°05'27.4" W.

Line BC

Adj Lat = +203.382 <- North
Adj Dep = -73.105 <- West

Because it's the NW quadrant, Brng = N 19°46'14.9" W

Line CD

Adj Lat = +192.340 <- North
Adj Dep = +198.635 <- East

Because it's the NE quadrant, Brng = N 45°55'20.7" E

Line DA

Adj Lat = -219.336 <- South
Adj Dep = +313.044 <- East

Because it's the SE quadrant, Brng = S 54°58'58.0" E

##### (3) Adjustment summary
 Adjusted Adjusted Line Lat (ft) Dep (ft) Length Bearing AB -176.386 -438.574 472.715 S 68°05'27.4" W BC +203.382 -73.105 216.122 N 19°46'14.9" W CD +192.340 +198.635 276.479 N 45°55'20.7" E DE -219.336 +313.044 382.237 S 54°58'58.0" E